Question

DIVIDE 16x³-8x²-4 by 4x​

Answer 1

Step-by-step explanation:

$\frac{16 {x}^{3} - 8 {x}^{2} - 4}{4x } = \frac{4(4 {x}^{3} - 2 {x}^{2} - 1) }{4x} \\ = \frac{4 {x}^{3} - 2 {x}^{2} - 1 }{x } \\ = \frac{x(4 {x}^{2} - 2x - \frac{1}{x} )}{x} \\ = 4 {x}^{2} - 2x - \frac{1}{x} answer..$