Question

divide 180 into two parts in ratio 2: 3​

Answer 1

$\sf \color{lime}{Question : }$

$\sf{divide \: 180 \: into \: two \: parts \: in \: ratio \: 2: 3}$

$\sf \red{Analysis}$

As given, we need to find two numbers that satisfy the ratio 2:3 and their sum must me 180. So we can take 2x + 3x = 180. So we have got the equation, Let's get started

$\sf \color{maroon}{Solution}$

$\sf{ : : : \implies2x + 3x = 180}$

$\sf{ : : : \implies5x = 180}$

$\sf{ : : : \implies x = \frac{180}{5} }$

$\sf \blue{ : : : \implies x = 36}$

$\sf{now, \: let \: us \: find \: the \: value \: of \: 2x \: and \: 3x}$

$\sf \pink{ : : : \implies 2x = 36 \times 2 = 72} \\ \sf \pink{ : : : \implies3x = 36 \times 3 = 108}$

$\sf \green{Verification}$

$\sf \purple{ \underbrace{ \overbrace{72 + 108 = 180}}}$$\sf \huge\color{orange}{ \checkmark}$

Answer 2

Answer:

°√We have to divide 180 in two parts such that they should be in ratio 3:2 . So, Let us take the ratio as "x". According to question, we should get 180 when we add 3x and 2x.