Question

divide 180 into two parts such that one third of one part may exceed one sixth of the other part by 6

Answer 1

Let one part be x.

Then the other part will be 180 - x.

Given that 1/3rd of one part may exceed 1/6th of another part by 6.

1/3 * x = 1/6(180 - x) + 6

6x = 3(180 - x) + 18(6)

6x = 540 - 3x + 108

6x + 3x = 540 + 108

9x = 648

x = 72.

If one part if 72.Then the other part will be 180 - x = 180 - 72 = 108.

hence the two parts are 72 and 108.

Verification:

1/3 * 72 = 1/6(108) + 6

24 = 18 + 6

24 = 24.


Hope this helps!