Question

Divide 180 into two parts such that the first part is 12 less than twice the second part

Answer 1

let
second part =x
first part=2x-12
sum of the parts =180
2x-12+x=180
3x=180+12
3x=192
x=192/3
x=64
therefore
second part=x=64
first part=2x-12=2*64-12=128-12=116

Answer 2

Step-by-step explanation:

it's the answer please follow me