divide 180 into two parts such that the first part is 12 less than twice the second part
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Answered by
18
X +(X-12)=180
2x-12=180
2x=180+12
2x=192
x=192\2
x=96
2x-12=180
2x=180+12
2x=192
x=192\2
x=96
siddhartharao77:
I think there should be 2 numbers
Answered by
29
Let the two numbers be x and y.
Given that Divide 180 into 2 parts.
x + y = 180 --------------- (1)
Given that the first part is 12 less than twice the second part.
x = 2y - 12 ---------------- (2)
Substitute (2) in (1), we get
2y - 12 + y = 180
3y - 12 = 180
3y = 192
y = 64.
Substitute y = 64 in (1), we get
x + 64 = 180
x = 180 - 64
x = 116.
Therefore the two parts are 64 and 116.
Verification:
x + y = 180
64 + 116 = 180
180 = 180.
Hope this helps!
Given that Divide 180 into 2 parts.
x + y = 180 --------------- (1)
Given that the first part is 12 less than twice the second part.
x = 2y - 12 ---------------- (2)
Substitute (2) in (1), we get
2y - 12 + y = 180
3y - 12 = 180
3y = 192
y = 64.
Substitute y = 64 in (1), we get
x + 64 = 180
x = 180 - 64
x = 116.
Therefore the two parts are 64 and 116.
Verification:
x + y = 180
64 + 116 = 180
180 = 180.
Hope this helps!
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