Question

divide 180 into two parts such that the first part is 12 less than twice the second part

Answer 1

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▶ Given :


i) Sum of two parts = 180


ii) The first part is 12 less than twice the second part



▶ Let :


i) Second part = x


ii) First part = 2x - 12



▶ According to the Question :



=> x + 2x - 12 = 180


=> 3x = 180 + 12


=> 3x = 192


=> x = 192 / 3


=> x = 64



•°• Second part = 64


•°• First part = 2x - 12


= 2 × 64 - 12


= 128 - 12


= 116




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Answer 2

Answer:

First part=64

Second part=116

Step-by-step explanation:

Let the two parts be x and (180-x)

Given

2x-12=180-x

3x=192

x=192/3

x=64

180-x=116