Question

divide 180 into two parts such that the first part is 12 less than twice the second part ​

Answer 1

Answer:

64 AND 116

Step-by-step explanation:

LET THE TWO PARTS BE X AND (2X-12)

=> X + (2X-12) = 180

=>              3X = 192

=>                X= 192/3=64.

=>     X=64   ;  2X-12=116

Answer 2

Answer:

Let

second part =x

first part=2x-12

sum of the parts =180

2x-12+x=180

3x=180+12

3x=192

x=192/3

x=64

therefore

second part=x=64

first part=2x-12=2*64-12=128-12=116