Divide 180into two parts such that the firs part is 12 less than twice the second part
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3
Answer:
116
Step-by-step explanation:
let
second part =x
first part=2x-12
sum of the parts =180
2x-12+x=180
3x=180+12
3x=192
x=192/3
x=64
therefore
second part=x=64
first part=2x-12=2*64-12=128-12=116
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