Divide 184 into parts such that one-third of one part may exceed one seventh of another part by 8
Answers
Answered by
5
Let one part be x
∴ The other part is (184 – x)
One-third of x = (x/3)
One-seventh of other part
Given that one-third of one part exceeds one-seventh of other part by 8.
⇒ 7x = 3(240 – x)
⇒ 7x = 720 – 3x
⇒ 10x = 720
∴ x = 72
Hence the two parts 72 and 112.
∴ The other part is (184 – x)
One-third of x = (x/3)
One-seventh of other part
Given that one-third of one part exceeds one-seventh of other part by 8.
⇒ 7x = 3(240 – x)
⇒ 7x = 720 – 3x
⇒ 10x = 720
∴ x = 72
Hence the two parts 72 and 112.
Similar questions