Math, asked by dev9365, 11 months ago

divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 8​

Answers

Answered by rameis89
4

1st part is x

2nd part is (184-x)

by question:

(184-x)1/3 - x1/7 = 8

x = 112 (one part)

therefore other part is 184-112 = 72

cross check: 112 x 1/7 = 16

72 x 1/3 = 24

and the difference is 8

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