divide 184 into two parts such that one third of one part may exceed one seventh of another part by 8
Answers
Step-by-step explanation:
Let one part be x
other part = (184-x)
1/3rd of one part exceeds 1/7th of the other by 8. Thus
(1/3 × x) - [1/7 × (184-x)] = 8
⇒ x/3 - (184/7 - x/7) = 8
⇒ x/3 - 184/7 + x/7 = 8
⇒ x/3 + x/7 - 184/7 = 8
⇒ x/3 + x/7 = 8 + 184/7
⇒ (7x+3x)/21 = (56+184)/7
⇒ 10x/21 = 240/7
⇒ x = 240/7 × 21/10
⇒ x = 72
So one part = 72
other part = 184 - 72 = 112
Answer:
The 2 parts are 72 and 112
Step-by-step explanation:
Let the 2 parts be x and y
Sum of parts = 184 = x + y ---------------------(1)
According To Question,
One-third of one part may exceed one seventh of another part by 8
=> x/3 - y/7 = 8
=> 7x - 3y = 168 ---------------------------(2)
From (1),
x + y = 184
=> y = 184 - x
Using the value of y in (2),
7x - 3(184 - x) = 168
=> 7x + 3x = 168 + 552
=> 10x = 720
=> x = 72
Using the value of x in (1),
72 + y = 184
=> y = 112
Therefore, the 2 parts are 112 and 72
HOPE IT HELPS!