Math, asked by bighnesh17, 11 months ago

divide 184 into two parts such that one third of one part may exceed one seventh of another part by 8 ​

Answers

Answered by Poonam2005
6

Step-by-step explanation:

Let one part be x

other part = (184-x)

1/3rd of one part exceeds 1/7th of the other by 8. Thus

(1/3 × x) - [1/7 × (184-x)] = 8

⇒ x/3 - (184/7 - x/7) = 8

⇒ x/3 - 184/7 + x/7 = 8

⇒ x/3 + x/7 - 184/7 = 8

⇒ x/3 + x/7 = 8 + 184/7

⇒ (7x+3x)/21 = (56+184)/7

⇒ 10x/21 = 240/7

⇒ x = 240/7 × 21/10

⇒ x = 72

So one part = 72

other part = 184 - 72 = 112

Answered by fheqiego
1

Answer:

The 2 parts are 72 and 112

Step-by-step explanation:

Let the 2 parts be x and y

Sum of parts = 184 = x + y  ---------------------(1)

According To Question,

One-third of one part may exceed one seventh of another part by 8

=> x/3 - y/7 = 8

=> 7x - 3y = 168  ---------------------------(2)

From (1),

x + y = 184

=> y = 184 - x

Using the value of y in (2),

7x - 3(184 - x) = 168

=> 7x + 3x = 168 + 552

=> 10x = 720

=> x = 72

Using the value of x in (1),

72 + y = 184

=> y = 112

Therefore, the 2 parts are 112 and 72

HOPE IT HELPS!

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