Question

Divide 184 into two parts such that one-third of one part may exceed one-seventh of the other part by 4​

Answer 1

Answer:

63.6 & 120.4

Step-by-step explanation:

x+y=184 ..eq1 where x = 184-y

x/3 = (y/7)+4

7x = 3y+84

sub. x = 184-y in above step

7(184-y) = 3y+84

1288-7y = 3y+84

10y = 1288-84

y = 120.4

then x = 63.6