Question

divide 184 into two parts such that one third of one part may exceed one seventh of another part by 8 ​

Answer 1

Answer:

The two parts are 72 and 112.

Explanation:

Let the two parts are x and 184−x.

then, x3=17(184−x)+8

⇒7x=3((184−x)+56)

⇒7x=552−3x+168

⇒10x=720

⇒x=72

So, other part = 184−72=112.

So, two parts are 72 and 112.