Math, asked by shujankumarpradhan, 1 year ago

divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 8
hint is - let the two parts be x and (184 - x). then 1/3 x-1/7 (184-x)

Answers

Answered by Swarup1998
36
◀HERE'S ⏬ YOUR ANSWER▶

Let, x and (184-x) are the two parts.

Then,
 \frac{1}{3} x -  \frac{1}{7} (184 - x) = 8 \\ or \:  \: 7x - 3(184 - x) = 168 \\ or \:  \: 10x = 720 \\ or \:  \: x = 72

Hence the numbers are 72 and 112.

⏏HOPE THIS ⬆ HELPS YOU⏏

shujankumarpradhan: Thanks you very much brother
Swarup1998: Pleased that it helped you.
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