divide 184 into two parts such that one third of one part may exceed one-seventh of other part by 8
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Answer:
1st part = 72
2nd part = 112
Step-by-step explanation:
let us take, 'x' be the 1st part
=> the 2nd part = 184-x
it is given that,
(1/3)x = (1/7)(184-x) + 8
=> (1/3)x = (1/7)(184) - (1/7)(x) + 8
=> (1/3)x + (1/7)(x) = (184/7) + 8
=> (7+3)/(7*3) * x = (184+56)/7
=> 10x/21 = 240/7
=> 10x = (240/7) * 21
=> 10x = 240*3
=> x = (240*3)/10
= 24*3
= 72
so, the 1st part = 72
and the 2nd part = 184-72 = 112
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