Math, asked by raj88663, 1 year ago

divide 184 into two parts such that one third of one part may exceed 1 7th of the other part 18

Answers

Answered by MarvelEdge17
1

Answer:

73.5  & 110.5

Step-by-step explanation:

Let one part be x. The other part will be 184-x

1/3 of x is greater than 1/17(184-x) by 18

So x/3 = (184-x)/17 + 18

x/3 = (184-x+306)/17

17x = 3(-x+490)

20x = 3 * 490

x = 73.5

The other part is 184 - 73.5 = 110.5

Similar questions