Question

divide 184 into two parts such that one third of one part may exceed one seventh of another part by 8​

Answer 1

Explanation-. Let one part be x ∴ The other part is (184 – x) One-third of x = (x/3) One-seventh of other part Given that one-third of one part exceeds one-seventh of other part by 8. ⇒ 7x = 3(240 – x) ⇒ 7x = 720 – 3x ⇒ 10x = 720 ∴ x = 72 Hence the two parts 72 and 112

Answer 2

let the first part be X

another part be (184-x) one-third of x

=x/3

one - seventh of another part=184-x/7

given that one third of a part exceeds one seventh of other part by 8

x/3 = 184-x/7 + 8

x/3=184-x +56/7

=7x = 3(240-x)

7x= 720-3x

10 x = 720

x = 72

hence the two part is 72 and 112.

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