Question

divide 184 into two parts such that one third of the part may exceed one seventh of the another part by 8​

Answer 1

Answer:

72 and 112

Step-by-step explanation:

Let the two parts of 184 be a and B

Then, according to question

a/3 = b/7 + 8

a/3 - b/7 = 8

(a/3 × 7/7) - (b/7 × 3/3) = 8

7a/21 - 3b/21 = 8

(7a - 3b)/21 = 8

7a - 3b = (8 × 21)

7a - 3b = 168 .....(1)

Also,

a + b = 184 ....(2)

Multiply equation (2) by 3

3a + 3b = 552 ....(3)

Add equations (1) and (3)

7a - 3b + 3a + 3b = 168 + 552

10a = 720

a = 72

If a = 72 then from equation (2)

a + b = 184

72 + b = 184

b = 184 - 72

b = 112