Question

Divide 189into two parts such that one third of one part may exceed one seventh of the other part by3

Answer 1

Let one part = x

and

the other part = (184-x)

:

"one third of one part may exceed one seventh of the other part by 8"

1%2F3x = 1%2F7(184-x) + 8

:

Multiply equation by 21 to get rid of the denominators; results:

7x = 3(184-x) + 21(8)

:

7x = 552 - 3x + 168

 

:

7x + 3x = 552 + 168

:

10x = 720

x = 720%2F10

x = 72 is one part

and

184 - 72 = 112 is the other part

;

:

Check these values in the statement

"one third of one part may exceed one seventh of the other part by 8"

1%2F3(72) = 1%2F7(112) + 8

24 = 16 + 8

Answer 2

Step-by-step explanation:

The 2 equations we form are as follows:-(x and y are two parts)

1)  x+y=189

2) x/3=y/7+3   =   63=7x-3y

Now solve for x and y.

Hope this helps.

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