Question

Divide 18m^2-6m^3+5m-110 by m+2

Answer 1

Hey mate !! Here you go : )

By remainder Theorem,

If p(x)= $m^2-6m^3+5m-110$

If q(x)= $m+2$

Equating q(x) to 0 :-

$m+2=0$

$m = -2$

Now P(-2)= $(-2)^2-6(-2)^3+5(-2)-110$

⇒ $4+48-10-110$

⇒ $-68$

Hence,the remainder is -68

Hope that helps you..

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Answer 2

Answer:

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