Math, asked by Callmebrainy, 1 day ago

Divide 18x^2 by 6x pls help algebra question

Answers

Answered by priyapsinha20
1

Answer:

Equation at the end of step 1

(2•32x2) - 6x = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

18x2 - 6x = 6x • (3x - 1)

Equation at the end of step

3

:

6x • (3x - 1) = 0

STEP

4

:

Theory - Roots of a product

4.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

4.2 Solve : 6x = 0

Divide both sides of the equation by 6:

x = 0

Solving a Single Variable Equation:

4.3 Solve : 3x-1 = 0

Add 1 to both sides of the equation :

3x = 1

Divide both sides of the equation by 3:

x = 1/3 = 0.333

Two solutions were found :

x = 1/3 = 0.333

x = 0

Answered by rvishall789
2

quotient=2x

remainder=0

dividend=18x^2

divisor=6x

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