Question

divide 18x^4y^2+15x^2y^2-27x^2y by 3xy
pls show working ​

Answer 1

Answer:

$\mathrm{Simplify}\:\frac{18x^4y^2+15x^2y^2-27x^2y}{3xy}:\quad x\left(6x^2y+5y-9\right)$

Step-by-step explanation:

$\mathrm{\frac{18x^4y^2+15x^2y^2-27x^2y}{3xy}}$

$=\frac{3x^2y\left(6x^2y+5y-9\right)}{3xy}$

$\mathrm{Cancel\:the\:common\:factor:}\:3$

$=\frac{x^2y\left(6x^2y+5y-9\right)}{xy}$

$\mathrm{Cancel\:the\:common\:factor:}\:y$

$=\frac{x^2\left(6x^2y+5y-9\right)}{x}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^b\cdot \:a^c$

$x^2=xx$

$=\frac{xx\left(6x^2y+5y-9\right)}{x}$

$\mathrm{Cancel\:the\:common\:factor:}\:x$

$=x\left(6x^2y+5y-9\right)$