Question

Divide 19 into two parts such that sum of their squares is 193

Answer 1

Answer:

7 and 12

Step-by-step explanation:

Let the 2 parts be x and (19-x), so that

(19-x)^2+x^2 = 193, or

361–38x+x^2+x^2–193 = 0

2x^2–38x+168=0, or

x^2–19x+84 = 0, or

(x-7)(x-12) = 0

So the two parts are 7 and 12.

Check: 12^2+7^2 = 144+49 = 193.