Divide 19into two part such that difference of their squares is
369
Answers
Answered by
1
Let first no. Be x Then second will be 19-x
Given,
X^2-(19-x)^2=369
X^2-(19^2+x^2-2(19)(x))=369
X^2-361-x^2+38x=369
38x=369+361
38x=730
X=730/38
X=19.2105236
19-x= -0.2105236
Therefore the two numbers are 19.2105236 and -0.2105236
Given,
X^2-(19-x)^2=369
X^2-(19^2+x^2-2(19)(x))=369
X^2-361-x^2+38x=369
38x=369+361
38x=730
X=730/38
X=19.2105236
19-x= -0.2105236
Therefore the two numbers are 19.2105236 and -0.2105236
Answered by
0
divide 19 into two parts such as difference of their squares is 485
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