Question

divide 1st term by second
polynomials
a³+b³+c³-3abc , a+b+c​

Answer 1

Answer:

a²+b²+c²-ab-bc-ca

Step-by-step explanation:

Let X=a³+b³+c³-3abc

=(a+b+c)(a²+b²+c²-ab-bc-ca)

Y=a+b+c

Now , X÷Y=(a+b+c)(a²+b²+c²-ab-bc-ca)÷(a+b+c)

=a²+b²+c²-ab-bc-ca(Ans)