Question

Divide 2√2x^4+6√2x^3+x^2 by 2√2x^2​

Answer 1

Step-by-step explanation:

$2 \sqrt{2} {x}^{4} + 6 \sqrt{2} {x}^{3} + {x}^{2} \div 2 \sqrt{2} {x}^{2} \\ = \frac{2 \sqrt{2} {x}^{4} }{2 \sqrt{2} {x}^{2} } + \frac{6 \sqrt{2} {x}^{3} }{2 \sqrt{2} {x}^{2} } + \frac{ {x}^{2} }{2 \sqrt{2 } {x}^{2} } \\ = {x}^{2} + 3x + \frac{1}{2 \sqrt{2} } \\ = 2 \sqrt{2} {x}^{2} + 3x + 1$