divide 2 + 7 x + 7 x square + 2 x cube by 2 X + 1
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Answer:
Let
f(x)=2x
3
–7x
2
+2x
And p must be added to f(x)
∴f
′
(x)=2x
3
–7x
2
+2x+p
Dividing f(x) by 2x−3 by long division method, we get
2x
3
–7x
2
+2x+p=(2x−3)(x
2
−2x−2)+(p−6)
Hence, remainder is p–6
⇒p−6=−2[given, remainder =−2]
⇒p=−2+6
⇒p=4
Therefore, 4 is to be added
Step-by-step explanation:
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