Question

divide 2 x cube+17x squre+2x-48 by 2x-3,find the quotient?​

Answer 1

Answer:

(2x³+17x²+2x-48) ÷ (2x-3)

=> ( 2x³+4x²+13x²+26x-24x-48) ÷ (2x-3)

=> ( 2x²(x+2) + 13x(x+2) - 24(x+2)) ÷ (2x-3)

=> ( (x+2) (2x²+13x-24) ) ÷ (2x-3)

=> ( (x+2) (2x²+16x-3x-24) ) ÷ (2x-3)

=> ( (x+2) {2x(x+8) - 3(x+8) } ) ÷ (2x-3)

=> ( (x+2) (x+8) (2x-3) ) ÷ (2x-3)

=> (x+2) (x+8) [canceling (2x-3) in the numerator and denominator]

=> x²+8x+2x+16

=> x²+10x+16

Answer 2

Step-by-step explanation:

Enclosure consists of solution.