Question

divide 2 x cube + 5 x square - 11 x - 14 by 2x+7​

Answer 1

$\frac{ {2x}^{3} + {5x}^{2} - 11x - 14 }{2x + 7} \\ \\ \\ = > 2 ( \frac{ - 7}{2} )^{3} + 5 ( \frac{ - 7}{2} )^{2} - 11 (\frac{ - 7}{2} ) - 14 \\ \\ = > 2( \frac{ - 343}{8} ) + 5( \frac{49}{4} ) + \frac{77}{2} - 14 \\ \\ = > \frac{ - 343}{4} + \frac{245}{4} + \frac{77}{2} - 14 \\ \\ = > \frac{ - 343 + 245 + 154 - 96}{4} \\ \\ = > \frac{ - 439 + 399}{4} = \frac{ - 40}{4} = { \red{- 10}}$

Hence, The remainder of division is -10.