Question

Divide 20 Chocolates between
ADI and Nikhil such that ADI gets 60 Percent while Nikhil gets 40 Percent of the Chocolates....​

Answer 1

Answer :-

• Adi got 12 chocolates and Nikhil got 8 chocolates.

Given :-

• Total chocolates = 20.
• Adi gets 60% chocolates and Nikhil gets 40% chocolates.

What to do?

• We have to divide these 20 chocolates in such a way that Adi gets 60% of the chocolates and Nikhil gets 40% of the chocolates.

Let's understand!

• There are 20 chocolates in total.

• We have to divide them between Adi and Nikhil such that Adi gets 60% while Nikhil gets 40% of the chocolates.

• To find their share, first we have to find out how much is 60% and 40% of the chocolates.

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Calculations :-

Let's find 60% of the chocolates.

Let's proceed!

$\sf60\% \: of \: 20$

Converting 60% into fraction,

$\sf\dfrac{6\!\!\! \not0}{1 \!\!\!\not0 \!\!\!\not0} \times 2 \!\!\!\not0$

Reducing the numbers,

$\sf \dfrac{6}{1} \times 2$

$\sf \dfrac{6}{1}$ can also be written as 6.

So let's multiply the remaining numbers.

$\sf6 \times 2$

Multiplying the numbers,

$\sf\rightarrow12.$

60% of 20 = 12.

Therefore, Adi got 12 chocolates.

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Calculations :-

Now, let's find 40% of the chocolates.

Let's proceed!

$\sf40\% \: of \: 20$

Converting 40% into fraction,

$\sf \dfrac{4\!\!\!\not0}{1 \!\!\!\not0\!\!\! \not0} \times 2\!\!\!\not0$

Reducing the numbers,

$\sf\dfrac{4}{1} \times 2$

$\sf \dfrac{4}{1}$ can also be written as 4.

So let's multiply the remaining numbers.

$\sf4 \times 2$

Multiplying the numbers,

$\sf\rightarrow 8.$

40% of 20 = 8.

Therefore, Nikhil got 8 chocolates.

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Final answer :-

Thus, Adi got 12 chocolates and Nikhil got 8 chocolates.