divide 20 into two parts so that the sumbpf their reciprocal is 4/15
Answers
Answered by
1
Let the two parts be x and y
So according to the question
Total = 20
So x + y = 20(1)
And 1/x + 1/y = 4/15(2)
solve (1) and (2)
u will get the answers ....
So according to the question
Total = 20
So x + y = 20(1)
And 1/x + 1/y = 4/15(2)
solve (1) and (2)
u will get the answers ....
Answered by
1
Let one number be x.
Then the other number will be 20-x.
Given that the sum of their reciprocal =4/15
1/x + 1/20- x = 4/15
20 - x + x = 4(x(20 - x)) /15^2
300 = 4(20x - x^2)
300 = 80x - 4x^2
4x^2 - 80x + 300 = 0
x^2 - 20x + 75 = 0
x^2 - 15x - 5x + 75 = 0
x(x - 15) - 5(x - 15) = 0
(x - 5)(x - 15) = 0
x = 5(or)x = 15.
Therefore the numbers are 5 and 15.
Hope this helps!
Then the other number will be 20-x.
Given that the sum of their reciprocal =4/15
1/x + 1/20- x = 4/15
20 - x + x = 4(x(20 - x)) /15^2
300 = 4(20x - x^2)
300 = 80x - 4x^2
4x^2 - 80x + 300 = 0
x^2 - 20x + 75 = 0
x^2 - 15x - 5x + 75 = 0
x(x - 15) - 5(x - 15) = 0
(x - 5)(x - 15) = 0
x = 5(or)x = 15.
Therefore the numbers are 5 and 15.
Hope this helps!
siddhartharao77:
Thanks bro for the brainliest
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