Question

Divide 20 into two parts such that one part is 8 more than the other. What are the two parts?



so let the one number be x
second number be x+8
as per question
x+x+8=20
2x+8=20
2x =20-8
2x=12
x= 12/2
x=6
one number=6
second number=x+8
=6+8
= 14
ans 14,6




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Answer 1

Answer:

let the one number be x

second number be x+8

as per question

x+x+8=20

2x+8=20

2x =20-8

2x=12

x= 12/2

x=6

one number=6

second number=x+8

=6+8

= 14

ans 14,6

Step-by-step explanation:

yes the answer is correct

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Answer 2

Answer:

Yes, your answer is correct. The numbers are 6 and 14.

Step-by-step explanation:

Let the first number be $x$.

Therefore, the another number be $x+8$.

According to question,

$x+(x+8)=20\\2x+8=20\\2x=20-8\\2x=12\\x=\frac{12}{2}\\x=6$

Therefore, the first number $x$ be 6.

And the other number $x+8=6+8=14$.