Question

Divide 20 into two parts such that the sum of the square of the parts is 232. What is the value of the two parts?

Answer 1

Answer:

14 and 6

Step-by-step explanation:

let 1 of those numbers be x

automatically other becomes 20-x

according to given condition

(20-x)^2+x^2=232

by using formula (a-b)^2 ,after solving we get 14 and 6

hope this may help you