Question

Divide 20 into two parts such that twice the square of the smaller part is 16 less than the square of the larger part

Answer 1

Answer:

assume smaller part as 'x'

so the larger part is(20-x)

2(20 – x)^2 = x^2 + 16

⇒ 2(400 – 40x + x^2) =  x^2 + 16

⇒ 800 – 80x + 2x^2 –  x^2 – 16 = 0

⇒ x^2– 80x + 784 = 0

Answer 2

Answer:

suppose big no x

small no x-20

a/c to ques

x2- (x-20)2=16

x2 -(x2-2×20x+400) =16

x2-x2+40x -400=16

40x = 416

x= 10.4

smaller 20-10.4= 9.6