Question

divide 20 into two parts such that twice the squareof the smaller number is 6 less than square of largest number

Answer 1

Answer:

Hi mate.

Correct question :

Divide 20 into two parts such that twice the square of the smaller part is 16 less than the square of the larger part. Solve it .

Answer :

Let the smaller part be x

Larger part be (20-x)

A/Q

2x²+16=(20-x)²

From this equation we get

X=-48,x=8,

Where x>0,

Hence x=8,and the numbers are

8 and

(20-x) =12

Hope it helps you mate.

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