Math, asked by mantumaji2001, 6 months ago

Divide 200 into 2 parts such that one fourth of the first part exceeds the one-twentieth of the other part by 14.
PLEASE ANSWER THIS QUESTION AS FAST AS YOU CAN AN I WILL MARK YOU AS BRAINLIEST.

Answers

Answered by adhyapoddar45
0

Step-by-step explanation:

Let one part be x and the other part be

x

200

3

1

x=

2

1

(

x

200

)[given]

3

x

=

x

100

⇒x

2

=300

x=

300

=10

3

1

st

part=x=10

3

, other part =

x

200

=

10

3

200

=

3

20

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