Question

Divide 200 into 4 parts in continued proportion
So that the ratio of the sum of the first and third
parts to the sum of the second and fourth may be
equal to 1:3

​

Answer 1

Answer:

Explanation:

Let be,

1/2A=1/3B=1/4C

A=2K

B=3K

C=4K

Where,

A:B:C=2:3:4

SO,

A=200×2/ (2+3+4)

A=400/9

B=200×3/(2+3+4)

B=600/9

C=200×4/(2+3+4)

C=800/9

Hope it will help you

Answer 2

Answer:

Step by Step explanation:

1/2A = 1/3B = 1/4C

A= 2K , B = 3K, C= 4K

A:B:C = 2:3:4

A = 200×2/(2+3+4)

A = 400 / 9

B = 200 × 3 / (2+3+4)

B = 600 / 9

C = 200 × 4 /(2+3+4)

C = 800 / 9