Question

Divide 200 into two parts such that 1/3 of the first and 1/2 of the second are equal​

Answer 1

Let one part be x.

Thus, other part = 200-x.

A/Q,

x/3=200-x/2

=> 2x= 600-3x

=> 5x=600

x=120.

Thus other number is 200-120=80.

Answer 2

Let the one part be x

Second part = 200 - x

1/3 rd of first part = \frac{1}{3}x

1/2 of second part = \frac{1}{2} (200-x)

We are given that 1/3rd of first and 1/2 of second are equal

So,  $\frac{1}{3}x = \frac{1}{2} (200-x)$

$\frac{1}{3} x = 100 - \frac{1}{2} x$

$\frac{1}{3} x + \frac{1}{2} x = 100$

$\frac{5}{6} x = 100$

$x = 100$ x $\frac{6}{5}$

x = 120

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