Question

divide 200 into two parts such that 4 times of the parts exceeded 3 times of the second part by 30

Answer 1

Answer:

Let the 1st part be x.So,the second part is (200-x).

So,for the second part

4x=3(200-x)+30

or,4x=600-3x+30

or,4x+3x=630

or,x=630/7=90

So,the 1st part is 90 and the 2nd part=(200-90)

=110

Answer 2

Answer:

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