Question

Divide 200 into two parts such that 4 times of the parts exceeded 3 times of the second part by 30

Answer 1

Answer:

Solution:-

Let the one part be 'x'

Then the other part will be 60 - x

So, according to the question.

3(60 - x) - 100 = 200 - 9(x)

180 - 3x - 100 = 200 - 9x

- 3x =9x = 200 + 100 - 180

6x = 120

x = 120/6 

x = 20 

Then the other part is 60 - 20 = 40

Answer.

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