Divide 207 in three parts, such that all parts are in A.p. and product of two smaller parts will be 4623
Answers
Let the three parts of 207 in A.P be (a - d) , a , (a + d) where, a > d
Now, clearly, (a + d) > a > (a - d)
Now, A to Q,
(a - d) + a + (a + d) = 207
=> 3a = 207
=> a = 69 --- (i) and,
(a - d) x a = 4623
=> 69 (69 - d) = 4623
=> d = (4761 - 4623)/69 = 2
Hence, a = 69 and d = 2
so, (a - d) = 67, a = 69 and (a + d) = 71
Hence, the three requred parts are, 67, 69 and 71
Answer:
Let the three parts of 207 in A.P be (a - d) , a , (a + d) where, a > d
Now, clearly, (a + d) > a > (a - d)
Now, A to Q,
(a - d) + a + (a + d) = 207
=> 3a = 207
=> a = 69 --- (i) and,
(a - d) x a = 4623
=> 69 (69 - d) = 4623
=> d = (4761 - 4623)/69 = 2
Hence, a = 69 and d = 2
so, (a - d) = 67, a = 69 and (a + d) = 71
Hence, the three requred parts are, 67, 69 and 71 Ans..!!
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