Divide 21000 into two parts such that the simple intrest on the first part for 3 years at 5% per annum is equal to the simple intrest on the second part for 5years at 4% per annum
Answers
Answer:
Let the parts be Rs. ‘x’ and Rs. (10000 – x)
∵ Simple interest = (Principal × Rate × Time)/100
Simple interest on Rs. x at 12.5% after 4 years = (x × 12.5 × 4)/100 = 0.5x
∵ Compound interest after n years = Principal × [(1 + Rate/100)n – 1]
Compound interest on Rs. (10000 – x) at 10% after 2 years
= (10000 – x) × [(1 + 10/100)2 – 1]
= (10000 – x) × 0.21
= 2100 – 0.21x
Now, total interest received = Rs. 3840
⇒ 0.5x + 2100 – 0.21x = 3840
⇒ 0.29x = 1740
⇒ x = 1740/0.29 = Rs. 6000
⇒ 10000 – x = Rs. 4000
∴ Required ratio = 6000 ∶ 4000 = 3 ∶ 2.
Answer:
the amount has to be divides =Rs.10000
Let Rs x be the first part
Then, second part =Rs.(10000−x)
Interest on first part =
100
x×12×4
=Rs.
25
12
x
Interest on second part
=(10000−x)×
100
16
×4.5
⇒Rs.(7200−
25
18
x)
According to question,
⇒
25
12
x=7200−
25
18
x
⇒
25
12
x+
25
18
x=7200
⇒
25
30
x=7200
⇒x=
30
7200×25
=Rs.6000
Second part =10000−6000