Math, asked by ushachowdary1981, 30 days ago

Divide 21000 into two parts such that the simple intrest on the first part for 3 years at 5% per annum is equal to the simple intrest on the second part for 5years at 4% per annum

Answers

Answered by kiranbhanot639
2

Answer:

Let the parts be Rs. ‘x’ and Rs. (10000 – x)

∵ Simple interest = (Principal × Rate × Time)/100

Simple interest on Rs. x at 12.5% after 4 years = (x × 12.5 × 4)/100 = 0.5x

∵ Compound interest after n years = Principal × [(1 + Rate/100)n – 1]

Compound interest on Rs. (10000 – x) at 10% after 2 years

= (10000 – x) × [(1 + 10/100)2 – 1]

= (10000 – x) × 0.21

= 2100 – 0.21x

Now, total interest received = Rs. 3840

⇒ 0.5x + 2100 – 0.21x = 3840

⇒ 0.29x = 1740

⇒ x = 1740/0.29 = Rs. 6000

⇒ 10000 – x = Rs. 4000

∴ Required ratio = 6000 ∶ 4000 = 3 ∶ 2.

thanks

Answered by gadsachin
0

Answer:

the amount has to be divides =Rs.10000

Let Rs x be the first part

Then, second part =Rs.(10000−x)

Interest on first part =

100

x×12×4

=Rs.

25

12

x

Interest on second part

=(10000−x)×

100

16

×4.5

⇒Rs.(7200−

25

18

x)

According to question,

25

12

x=7200−

25

18

x

25

12

x+

25

18

x=7200

25

30

x=7200

⇒x=

30

7200×25

=Rs.6000

Second part =10000−6000

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