Divide 215 inTo 3 parts such that 1st part is 2/5 of second and the ratio between 2nd a d 3rd is 4:3
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Given: the number 215 is divided into three parts with given conditions
To find: the parts
Solution:
Let the parts be x, y and z
- The 1st part is 2/5 of the 2nd gives
- x = 2/5 * y ... ...(1)
- The ratio between 2nd and the 3rd is 4 : 3 gives
- y : z = 4 : 3
- or, y/z = 4/3
- or, z = 3/4 * y ... ...(2)
- Since the sum of the parts must be 215. We get
- x + y + z = 215
- or, 2/5 * y + y + 3/4 * y = 215 [ by (1) and (2) ]
- or, (2/5 + 1 + 3/4) * y = 215
- or, (8 + 20 + 15)/20 * y = 215
- or, 43/20 * y = 215
- or, y = 215 * 20/43
- or, y = 100
- Putting y = 100 in (1), we get
- x = 2/5 * 100
- or, x = 40
- Putting y = 100 in (2), we get
- z = 3/4 * 100
- or, z = 75
Answer: the three parts are 40, 100 and 75.
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