Math, asked by mskediga, 1 month ago

divide 22(x⁴-5x³-24x²) by 11x (x-8)​

Answers

Answered by tennetiraj86
4

Step-by-step explanation:

Given:-

22(x^4 -5x^3 - 24x^2)

To find:-

Divide 22(x^4 -5x^3 - 24x^2) by 11x (x-8)

Solution:-

Method-1:-

Solving by factorization:-

Given expression is 22(x^4 -5x^3 - 24x^2)

On dividing 22(x^4 -5x^3 - 24x^2) by 11x (x-8)

=> 22(x^4 -5x^3 - 24x^2) ÷ 11x (x-8)

=> 22(x^4 -5x^3 - 24x^2) / 11x (x-8)

=> (11×2)[x^2×x^2-5×x^2×x- 24×x^2) / 11x (x-8)

=> (11×2)(x^2)[x^2-5x -24)/11x(x-8)

On cancelling 11x in both numerator and the denominator

=> 2x(x^2-5x-24)/(x-8)

=> 2x(x^2+3x-8x-24)/(x-8)

=>2x[x(x+3)-8(x+3)]/(x-8)

=>2x(x+3)(x-8)/(x-8)

On cancelling (x-8) in both numerator and the denominator

=> 2x(x+3)

=>2x^2+6x

22(x^4 -5x^3 - 24x^2) ÷ 11x (x-8) = 2x^2+6x

Method-2:-

Solving by Division:-

See the above attachment

Answer:-

22(x^4 -5x^3 - 24x^2) ÷ 11x (x-8) = 2x^2+6x

Used Method:-

  • Factorization method

  • Division Method
Attachments:
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