Question

Divide 232 into two parts such that twice one part is 48 more than six times the other part.

Answer 1

Answer:

Let one part = x then other part is (232–x).

now, a/q

$2x - 48 = (232 - x) \times 6$

$2x - 48 = 1392 - 6x$

$2x + 6x = 1392 + 48 = 1440$

$8x = 1440$

$x = \frac{1440}{8} = 180$

so one part is 180 & other part is 232–180 = 52 Ans.