Question

Divide 232 into two parts such that twice one part is 48 more than six times the other part.

Answer 1

Step-by-step explanation:

Let one part be x and other part be 232 - x...

A.T.Q,

$2x = 48 + 6(232 - x) \\ \\ = > 2x = 48 + 1392 - 6x \\ \\ = > 2x + 6x = 1440$

$= > 8x = 1440 \\ \\ = > x = \frac{1440}{8} = 180$

Therefore, one part is x = 180.... and the other part is 232 - x = 232 - 180 = 52....

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