Math, asked by asinjeenath63, 5 months ago

Divide 24(a²bc + ab²c + abc²) by 8abc

Answers

Answered by Anonymous

5

Answer:

3(a+b+c)

Step-by-step explanation:

24(a²bc + ab²c + abc²) / 8abc

= 24abc(a+b+c) / 8abc

= 3(a+b+c)

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