Question

Divide 24 in three parts such that they are in AP and their product is 440.

Answer 1

Let the required term of the given of the given AP be a-d,a and a+d
Where the first term is a-d
The common difference = d
Given: the sum of three parts =24
Therefore, (a-d)+(a)+(a+d) = 24
3a = 24
a = 8
Given : the product of these three terms = 440
Therefore, (a-d)(a)(a+d) =440
(8-d)(8)(8+d) = 440
-8dsquare + 512 = 440
-8dsquare = 440-512
-8d square = -72
d square = 72/8
d square = 9
d = 3
So, the three required terms of AP is 8-3 = 5 ; 8 and 8+3 = 11 Three terms are 5,8 and 11

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Answer 2

Here is your solution.