Question

Divide 24 in three parts such that they are in AP and their product is 440?

Answer 1

Solution:-
Let the required terms of the given AP be a-d, a and a+d
Where the first term is a-d
The common difference = d
Given : The sum of the three parts = 24
∴ (a-d)+(a)+(a+d) = 24
3a = 24
a = 8
Given : The product of these three terms = 440
∴ (a-d) (a) (a+d) = 440
(8-d) (8) (8+d) = 440
- 8d² + 512 = 440
- 8d² = 440 - 512
- 8d² = - 72
d² = 72/8
d² = 9
d = √9
d= 3
So the three required terms of AP is 8 - 3 = 5 ; 8 and 8 + 3 = 11
Three terms are 5, 8, 11
Answer.

Answer 2

Answer:

Step-by-step explanation:

Solution:-

Let the required terms of the given AP be a-d, a and a+d

Where the first term is a-d

The common difference = d

Given : The sum of the three parts = 24

∴ (a-d)+(a)+(a+d) = 24

3a = 24

a = 8

Given : The product of these three terms = 440

∴ (a-d) (a) (a+d) = 440

(8-d) (8) (8+d) = 440

- 8d² + 512 = 440

- 8d² = 440 - 512

- 8d² = - 72

d² = 72/8

d² = 9

d = √9

d= 3

So the three required terms of AP is 8 - 3 = 5 ; 8 and 8 + 3 = 11

Three terms are 5, 8, 11

Answer.

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