Question

divide 24(x²yz+xy²z+xyz²)by 8xyz using both methods.

Answer 1

=24x²yz+24xy²z+24xyz²/8xyz
=24x²yz/8xyz + 24xy²z/8xyz +
24xyz²/8xyz
=3x + 3y + 3z
=3(x+y+z)

Answer 2

Answer:

The answer is 3(x +y +z)

Step-by-step explanation:

Given,

to divide   24(x²yz+xy²z+xyz²) by 8xyz

METHOD 1:

We can take xyz common from the given dividend , i.e.,           24(x²yz+xy²z+xyz²) = $24 (x \times y \times z) (x + y +z)$

now let's divide it with 8xyz,

                               =$\frac{24 (x \times y \times z) (x + y +z)}{8 (x \times y \times z)}$

cancel the common terms and we get answer as,  

                               = 3 (x+ y + z).

METHOD 2:  (Long division method )

$8xyz \overline{)24(x^{2} yz+x y^{2}z +xyz^{2} )}$$8xyz \overline{)24(x)\times ( xyz)+24(y)\times ( yxz) +24(z)\times ( yxz)}$

    Further solve it by taking the quotient as 3(x +y +z) and you get reminder as zero.  

Therefore, 3(x +y+ z) is the answer when  24(x²yz+xy²z+xyz²) is divided by  8xyz